Open Journal of Mathematical Analysis

Global existence, uniqueness, and asymptotic behavior of solution for the Euler-Bernoulli viscoelastic equation

Mohamed Mellah1, Ali Hakem
Faculty of Exact Sciences and Computer Science, Hassiba Benbouali University of Chlef, Chlef Algeria.; (M.M)
Laboratory ACEDP, Djillali Liabes University, 22000 Sidi Bel Abbes, Algeria.; (A.H)
1Corresponding Author: m.mellah@univ-chlef.dz

Abstract

We study the global existence and uniqueness of a solution to an initial boundary value problem for the Euler-Bernoulli viscoelastic equation utt+Δ2ug1Δ2u+g2Δu+ut=0. Further, the asymptotic behavior of solution is established.

Keywords:

Euler-Bernoulli viscoelastic equation, global existence, asymptotic behavior, memory.

1. Introduction

This work is concerned with the global existence, uniqueness, and asymptotic behavior of solution for the Euler-Bernoulli viscoelastic equation
{utt+Δ2ug1Δ2u+g2Δu+ut=0,xΩ, t>0,u(x,0)=u0(x),ut(x,0)=u1(x),xΩ,u=0,uν=0,xΩ, t>0,
(1)
where Ω is a bounded domain of Rn with smooth boundary Ω, and ν is the unit outer normal on Ω. Here g1 and g2 are positive functions satisfying some conditions to be specified later, and giχ(t)=t0gi(tτ)χ(τ)dτ,i=1,2. The Euler-Bernoulli equation
utt(x,t)+Δ2u(x,t)+h(ut)=f(u),(x,t)Rn×(0,),
(2)
describes the deflection u(x,t) of a beam (when n=1) or a plate (when n=2), where Δ2u:=Δ(Δu)=nj=1(ni=1uxiuxi)xjxi, and h and f represent the friction damping and the source respectively.
Lange and Menzala [1] considered
utt(x,t)+Δ2u(x,t)+a(t)ut(x,t)=0
(3)
where xRn, t0, a(t)=m(v(,t)2L2(Rn) and the real-valued function m:[0,+)[1,+) will be assumed to be of class C1 satisfying the condition m(s)1+s for all s0. They remarked that the imaginary part of the solutions of Schr\"{o}dinger's equation iwt=Δw+im((Imw)2L2(Rn)Rew=0, are precisely the solutions for (3). Then, using Fourier transform, the existence of global classical solutions and algebraic decay rate were proved for initial data whose regularity depends on the spacial dimension n. Messaoudi [2] studied the equation
utt(x,t)+Δ2u(x,t)+a|ut|m2ut=b|u|p2u,
(4)
where a,b>0, p,m>2. He established an existence result for (4) and showed that the solution continued to exist globally if mp. If we take the viscoelastic materials into consideration, the model (2) becomes
utt(x,t)+Δ2u(x,t)t0g(ts)Δ2u(x,s)ds+h(ut)=f(u),
(5)
where g is so-called viscoelastic kernel. The term t0g(ts)Δ2u(x,s)ds describes the hereditary properties of the viscoelastic materials [3]. It expresses the fact that the stress at any instant t depends on the past history of strains which the material has undergone from time 0 up to t. Tatar [4] obtained the property of the energy decay of the model (5) for h=f=0 and from this, we know that the term t0g(ts)Δ2u(x,s)ds, similar to the friction damping, can cause the inhibition of the energy. Messaoudi and Mukiawa [5] studied the fourth-order viscoelastic plate equation utt(x,t)+Δ2u(x,t)t0g(ts)Δ2u(x,s)ds=0, in the bounded domain Ω=(0,π)×(l,l)R2 with nontraditional boundary conditions. The authors established the well-posedness of the solution and a decay result.
Rivera et al. [6] investigated the plate model: utt+Δ2uσΔutt+t0g(ts)Δ2u(s)ds=0, in the bounded domain ΩR2 with mixed boundary condition and suitable geometrical hypotheses on Ω. They established that the energy decays to zero with the same rate of the kernel g such as exponential and polynomial decay. To do so in the second case they made assumptions on g,g and g which means that g(1+t)p for p>2. Then they obtained the same decay rate for the energy. However, their approach can not be applied to prove similar results for 1<p2.
Cavalcanti et al. [7] investigated the global existence, uniqueness and stabilization of energy of utt+Δ2ut0g(ts)Δ2u(s)ds+a(t)ut=0 where a(t)=M(Ω|u(x,t)|2dx)  with   MC1([0,+)).

By taking a bounded or unbounded open set Ω where M(s)>m0>0 for all s0, the authors showed in [7] that the energy goes to zero exponentially, provided that g goes to zero at the same form.

The aim of this work is to study the global existence of regular and weak solutions of problem (1) for the bounded domain, then for ξ:R+R+ a increasing C2 function such that
ξ(0)=0,ξ(0)>0,limt+ξ(t)=+,ξ(t)<0t0.
(6)
the solution features the asymptotic behavior E(t)E(0)eκξ(t),t0, where E(t) is defined in (38) and κ is a positive constant independent of the initial energy E(0).

2. Preliminaries and main results

We begin by introducing some notation that will be used throughout this work. For functions u(x,t), v(x,t) defined on Ω, we introduce (u,v)=Ωu(x)v(x)dx  and  u2=(Ω|u(x)|2dx)12. Define X={uH20(Ω);Δ2uL2(Ω)} Then, X is a Hilbert space endowed with the natural inner product (u,v)X=(u,v)H20+(Δ2u,Δ2v). Now let us precise the hypotheses on g1 and g2.
(H1) g1:R+R+ is a bounded function satisfying g1(t)C2(R+)L1(R+),g1(0)>0. (H2) There exist positive constants α1,α2 and α3 such that α1g1(t)g1(t)α2g1(t),t0, (H3) 0g1(t)α3g1(t),t0, (H4) g2:R+R+ is a bounded function satisfying g2(t)C1(R+)L1(R+),g2(0)>0. (H5) There exist positive constants η1 and η2 such that η1g2(t)g2(t)η2g2(t),t0, (H6) 1t0(g1(s)+λ11g2(s))ds=l>0, where λ1>0 is the first eigenvalue of the spectral Dirichlet problem Δ2u=λ1u in  Ω,u=uν=0  in  Ω, u21λ1Δu2.

Lemma 1. For ϕ,ψC1([0,+[,R) we have 2t0Ωϕ(ts)ψψdxds=ddt((ϕψ)(t)t0ϕ(s)dsψ22)+(ϕψ)(t)ϕ(t)ϕ22, where (ϕψ)(t)=t0ϕ(ts)ψ(t)ψ(s)22ds.

Theorem 2. Assume that (H1)(H6) hold, and that {u0,u1} belong to H20(Ω)×L2(Ω). Then, Problem (1) admits a unique weak solution u in the class uC0([0,);H20(Ω))C1([0,);L2(Ω)). Moreover, for ξ:R+R+ a increasing C2 function satisfying (???) and, if g1L1(0,) is sufficiently small, we have for κ>0 E(t)E(0)eκξ(t),t0.

3. Existence of Solutions

In this section we first prove the existence and uniqueness of regular solutions to Problem (1). Then, we extend the same result to weak solutions using density arguments.

3.1. Regular solutions

Let (wj) be a Galerkin basis in X, and let Vm be the subspace generated by the first m vectors w1,...,wm. We search for a function um(t)=mi=1kim(t)wi(x), m=1,2,.... satisfying the approximate Cauchy problem
(um(t),v)+(Δum(t),Δv)t0g1(ts)(Δum(s),Δv)dst0g2(ts)(um(s),v)ds+(um(t),v)=0,vVm,
(7)
um(0)=u0mu0  in   X  and   um(0)=u1mu1   in   H20(Ω).
(8)
By standard methods in differential equations, we can prove the existence of solutions to the problem (5)(6) on [0,tm) with 0<tm<T. In order to extend the solution of (7)(8) to the whole [0,T], we need the following priori estimate.
Estimate 1. Taking v=2um(t) in (7), we have
ddt[um(t)22+Δum(t)22]+2um(t)222t0g1(ts)Δum(s)Δum(t)dxds2t0g2(ts)um(s)um(t)dxds=0.
(9)
Using Lemma 1, we obtain
2t0g1(ts)ΩΔum(s)Δum(t)dxds=ddt{(g1Δum)(t)(t0g1(s)ds)Δum(t)22}(g1Δum)(t)+g1(t)Δum(t)22,
(10)
and
2t0g2(ts)Ωum(s)um(t)dxds=ddt{(g2um)(t)(t0g2(s)ds)um(t)22}(g2um)(t)+g2(t)um(t)22,
(11)
Inserting Equations (10) and (11) into Equation (9) and integrating over [0,t][0,T], we obtain
um(t)22+(1t0g1(s)ds)Δum(t)22+(g1Δum)(t)(t0g2(s)ds)um(t)22+(g2um)(t)+2t0um(s)22dst0(g1Δum)(s)ds+t0Ωg1(s)|Δum(s)|2dxdst0(g2um)(s)ds+t0Ωg2(s)|um(s)|2dxds=u1m(t)22+Δu0m22.
(12)
By using the fact that (g1Δum)(t)+(g2um)(t)t0(g1Δum)(s)dst0(g2um)(s)ds+t0Ωg1(s)|Δum(s)|2dxds+t0Ωg2(s)|um(s)|2dxds0, and (1t0g1(s)ds)Δum(t)22(t0g2(s)ds)um(t)22(1t0[g1(s)+λ11g2(s)]ds)Δum(t)22lΔum(t)22, Equation (12) yields
um(t)22+lΔum(t)22+2t0um(s)22dsu1m(t)22+Δu0m22.
(13)
Taking the convergence of Equation (8) into consideration, we arrive at
um(t)22+lΔum(t)22+2t0um(s)22dsL1.
(?)
where L1=u122+Δu022.
Estimate 2. Firstly, we obtain an estimate for um(0) in the L2 norm. indeed, setting v=um(0) and t=0 in Equation (7), we obtain
um(0)22[Δ2u0m2+u1m2]um(0)2.
(?)
From Equations (8), (14) and (15), it follows that
um(0)2L2,mN,
(16)
where L2 is a positive constant independent of mN. Differentiating Equation (7) with respect to t, and setting v=um(t), we obtain
ddt[12um(t)22+12Δum(t)22]+um(t)22=g1(0)ΩΔ2um(t)um(t)dxΩt0g1(ts)Δ2um(s)um(t)dsdxg2(0)ΩΔum(t)um(t)dxΩt0g2(ts)Δum(s)um(t)dsdx=g2(0)ΩΔum(t)um(t)dxΩt0g2(ts)Δum(s)um(t)dsdxg1(0)Δum(t)22+g1(0)ddtΩΔum(t)Δum(t)dx+ddt{t0g1(ts)ΩΔum(t)Δum(t)dxds}g1(0)ΩΔum(t)Δum(t)dxt0g1(ts)ΩΔum(s)Δum(t)dxds.
(17)
By (H5), H\"{o}lder's inequality and Young's inequality give
Ωt0g2(ts)Δum(s)um(t)dsdx12um(t)22+η21g2L12t0g2(ts)Δum(s)22ds.
(18)
From Equation (14) we obtain
g2(0)ΩΔum(t)um(t)dx12um(t)22+[g2(0)]2L12l
(19)
and
g1(0)ΩΔum(t)Δum(t)dx|g1(0)|2(Δum(t)22+Δum(t)22)|g1(0)|L12l+|g1(0)|2Δum(t)22.
(20)
From (H3), we deduce
Ωt0g1(ts)Δum(s)Δum(t)dsdx12Δum(t)22+α23g1L12t0g1(ts)Δum(s)22ds
(21)
Inserting Equations (18)-(21) in Equation (17), we get
12um(t)22+12Δum(t)22um(0)22+Δu1m22+C3+g1(0)ΩΔum(t)Δum(t)dx+t0g1(ts)ΩΔum(t)Δum(t)dxds+C4t0Δum(s)22ds,
(22)
where C3=[η21g2L12+[g2(0)]2L12l+|g1(0)|L12l]T+[η21g2L1(0,)g2L(0,)2+α21g1L1(0,)g1L(0,)2]L1Tl and C4=|g1(0)|2+12. Using H\"{o}lder's inequality, we know that, for any δ>0,
g1(0)ΩΔum(t)Δum(t)dx+t0g1(ts)ΩΔum(t)Δum(t)dxds2δΔum(t)22+[g1(0)]24δΔum(t)22+α214δg1L1(0,)g1L(0,)t0Δum(s)22ds2δΔum(t)22+C5,
(23)
where C5=[[g1(0)]24δ+α214δg1L1(0,)g1L(0,)T]L1l. Combining Equation (22) and Equation (23), we get
12um(t)22+(122δ)Δum(t)22um(0)22+Δu1m22+C3+C5+C4t0Δum(s)22ds,
(24)
Fixing δ>0, sufficiently small, so that 122δ>0 in Equation (24), and taking into account Equations (8) and (16), we get from Gronwall's Lemma the second estimate,
um(t)22+Δum(t)22L3,
(25)
where L3 is a positive constant independent of mN and t[0,T].
Estimate 3. Let m1m2 be two natural numbers, and consider zm=um1um2. Then, applying the same way as in the estimate 1 and observing that {u0m} and {u1m} are Cauchy sequence in X and H20(Ω), respectively, we deduce
zm(t)22+Δzm(t)22+2t0zm(s)22ds0,  as   n+,
(26)
for all t[0,T].
Therefore, from Equations (24), (25) and (26), we deduce that there exist a subsequence {uμ} of {um} and u such that
uμu  strongly in   C0([0,T];L2(Ω)),
(27)
uμu  strongly in   C0([0,T];H20(Ω)),
(28)
uμu  weakly star in   L(0,T;L2(Ω)).
(29)
The above convergences (27)-(29) are enough to pass to the limit in Equation (7), to obtain u+Δ2ut0g1(ts)Δ2u(s)ds+t0g2(ts)Δu(s)ds+u=0  in   L(0,;L2(Ω)),u(0)=u0,u(0)=u1.. Next, we want to show the uniqueness of solution of (7)-(8). Let u(1), u(2) be two solutions of (7)-(8). Then z=u(1)u(2) satisfies
(z(t),v)+(Δz(t),Δv)t0g1(ts)(Δz(s),Δv)dst0g2(ts)(z(s),v)ds+(z(t),v)=0,vH20(Ω),
(30)
z(x,0)=z(x,0)=0,xΩ, z=0,zν=0,xΩ, t>0. Setting v=2z(t) in (30), then as in deriving (14), we see that
z(t)2=Δz(t)2=0  for all   t[0,T].
(31)
Therefore, we have the uniqueness.

3.2. Weak solutions

Let (u0,u1)H20(Ω)×L2(Ω). Then, since X×H20(Ω) is dense in H20(Ω)×L2(Ω) there exists (u0μ,u1μ)X×H20(Ω) such that
u0μu0  in   H20(Ω)  and   u1μu1  in   L2(Ω).
(32)
Then, for each μN, there exists a unique regular solution uμ of Problem (1) in the class
uμL(0,;H20(Ω)),uμL(0,;H20(Ω)),uμL(0,;L2(Ω)).
(33)
In view of Equation (33) and using an analogous argument to that in Estimate 1 and Estimate 3, we find a sequence {uμ} of solutions to Problem (1) such that
uμu  weak star in   L(0,T;L2(Ω)),
(34)
uμu  weak star in   L(0,T;H20(Ω)),
(35)
uμu  strongly in   C0([0,T];H20(Ω)),
(36)
uμu  strongly in   C0([0,T];L2(Ω)),
(37)
The convergences (33)-(36) are sufficient to pass to the limit in order to obtain a weak solution of Problem (1), which satisfies u+Δ2ut0g1(ts)Δ2u(s)ds+t0g2(ts)Δu(s)ds+u=0  in   L2(0,;H2(Ω)),u(0)=u0,u(0)=u1.. The uniqueness of weak solutions requires a regularization procedure and can be obtained using the standard method of Visik-Ladyzhenskaya, c.f. Lions and Magenes [8, Chap. 3, Sec. 8.2.2].

4. Asymptotic Behaviour

In this section, we discuss the asymptotic behavior of the above-mentioned weak solutions. Let us define the energy associated to Problem (1) as
E(t)=12ut(t)22+12(1t0g1(s)ds)Δu(t)22+12(g1Δu)(t)12(t0g2(s)ds)u(t)22+12(g2u)(t).
(38)
To demonstrate our decay result, the lemmas below are essential.

Lemma 3. For any t>0 0E(t)12[ut(t)22+Δu(t)22+(g1Δu)(t)+(g2u)(t)].

Proof. Using the fact that u(t)22λ11Δu(t)22, we have (1t0g1(τ)dτ)Δu(t)22(t0g2(τ)dτ)u(t)22(1t0[g1(s)+λ11g2(s)]ds)Δu(t)22 and according to (H6) we have E(t)0,
and E(t)=12ut(t)22+12Δu(t)22+12(g1Δu)(t)+12(g2u)(t)12{(t0g1(s)ds)Δu(t)22+(t0g2(s)ds)u(t)22}12[ut(t)22+Δu(t)22+(g1Δu)(t)+(g2u)(t)].

Lemma 4. The energy E(t) satisfies

E(t)ut(t)2212α2(g1Δu)(t)12η2(g2u)(t)12[g1(0)α1g1L1(0,)]Δu(t)220.
(39)

Proof. Multiplying the first equation in (1) by ut and integrating over Ω, we obtain ddt[12ut(t)22+12Δu(t)22]+ut(t)22=t0g1(tτ)Δu(τ)Δut(t)dxdτ+t0g2(tτ)u(τ)ut(t)dxdτ. Exploiting (10)-(11) and by (H1)(H5), we deduce

E(t)=ut(t)22+12(g1Δu)(t)12g1(t)Δu(t)22+12(g2u)(t)12g2(t)u(t)22ut(t)2212α2(g1Δu)(t)12η2(g2u)(t)12g1(t)Δu(t)22.
(40)
From assumptions (H2) and since \int_{0}^{t}g_{1}'(\tau)d\tau=g_{1}(t)-g_{1}(0), we obtain
\begin{eqnarray}\label{eq41} -\frac{1}{2}g_{1}(t)\|\Delta u(t)\|_{2}^{2}&=&-\frac{1}{2}g_{1}(0)\|\Delta u(t)\|_{2}^{2}-\frac{1}{2}\left(\int_{0}^{t}g_{1}'(s)ds\right)\|\Delta u(t)\|_{2}^{2}\nonumber\\ &\leq&-\frac{1}{2}g_{1}(0)\|\Delta u(t)\|_{2}^{2}+\frac{\alpha_{1}}{2}\|g_{1}\|_{L^{1}(0,\infty)}\|\Delta u(t)\|_{2}^{2}\nonumber\\ &=&-\frac{1}{2}\left[g_{1}(0)-\alpha_{1}\|g_{1}\|_{L^{1}(0,\infty)}\right]\|\Delta u(t)\|_{2}^{2}. \end{eqnarray}
(41)
Combining Equation (40) and Equation (41), we conclude that \begin{eqnarray*} E'(t)&\leq&-\|u_{t}(t)\|^{2}_{2}-\frac{1}{2}\alpha_{2}(g_{1}\square\Delta u)(t)-\frac{1}{2}\eta_{2}(g_{2}\square\nabla u)(t)\nonumber\\ &&-\frac{1}{2}\left[g_{1}(0)-\alpha_{1}\|g_{1}\|_{L^{1}(0,\infty)}\right]\|\Delta u(t)\|^{2}_{2}\leq0. \end{eqnarray*} Multiplying Equation (39) by e^{\kappa\xi(t)} (\kappa>0) and utilizing Lemma 3, we have
\begin{eqnarray}\label{eq42} \frac{d}{dt}\left(e^{\kappa\xi(t)}E(t)\right)&\leq&-e^{\kappa\xi(t)}E(t)\|u_{t}(t)\|^{2}_{2} -\frac{1}{2}\alpha_{2}(g_{1}\square\Delta u)(t)e^{\kappa\xi(t)}E(t)-\frac{1}{2}\eta_{2}(g_{2}\square\nabla u)(t)e^{\kappa\xi(t)}E(t)\nonumber\\ &&-\frac{1}{2}\left[g_{1}(0)-\alpha_{1}\|g_{1}\|_{L^{1}(0,\infty)}\right]e^{\kappa\xi(t)}E(t)\|\Delta u(t)\|^{2}_{2}+\kappa\xi'(t)e^{\kappa\xi(t)}E(t)\nonumber\\ &\leq&-\frac{1}{2}\left[2-\kappa\xi'(t)\right]e^{\kappa\xi(t)}E(t)\|u_{t}(t)\|^{2}_{2} -\frac{1}{2}\left[\alpha_{2}-\kappa\xi'(t)\right]e^{\kappa\xi(t)}E(t)(g_{1}\square\Delta u)(t)\nonumber\\ &&-\frac{1}{2}\left[\eta_{2}-\kappa\xi'(t)\right]e^{\kappa\xi(t)}E(t)(g_{2}\square\nabla u)(t)\nonumber\\ &&-\frac{1}{2}\left[g_{1}(0)-\alpha_{1}\|g_{1}\|_{L^{1}(0,\infty)}-\kappa\xi'(t)\right]e^{\kappa\xi(t)}E(t)\|\Delta u(t)\|^{2}_{2}. \end{eqnarray}
(42)
Using the fact that \xi' is decreasing we arrive at
\begin{eqnarray}\label{eq43} \frac{d}{dt}\left(e^{\kappa\xi(t)}E(t)\right) &\leq&-\frac{1}{2}\left[2-\kappa\xi'(0)\right]e^{\kappa\xi(t)}E(t)\|u_{t}(t)\|^{2}_{2} -\frac{1}{2}\left[\alpha_{2}-\kappa\xi'(0)\right]e^{\kappa\xi(t)}E(t)(g_{1}\square\Delta u)(t)\nonumber\\ &&-\frac{1}{2}\left[\eta_{2}-\kappa\xi'(0)\right]e^{\kappa\xi(t)}E(t)(g_{2}\square\nabla u)(t)\nonumber\\ &&-\frac{1}{2}\left[g_{1}(0)-\alpha_{1}\|g_{1}\|_{L^{1}(0,\infty)}-\kappa\xi'(0)\right]e^{\kappa\xi(t)}E(t)\|\Delta u(t)\|^{2}_{2}. \end{eqnarray}
(43)
Choosing \|g_{1}\|_{L^{1}(0,\infty)} sufficiently small so that g_{1}(0)-\alpha_{1}\|g_{1}\|_{L^{1}(0,\infty)}=L>0, and choosing \kappa sufficiently small in order to have 2-\kappa\xi'(0)>0,\quad \alpha_{2}-\kappa\xi'(0)>0,\quad \eta_{2}-\kappa\xi'(0)>,\quad L-\kappa\xi'(0)>0. from Equation (43) we arrive at
\begin{equation}\label{eq44} \frac{d}{dt}\left(e^{\kappa\xi(t)}E(t)\right)\leq0,\quad t>0. \end{equation}
(44)
Integrating the above inequality over (0,t), it follows that
\begin{equation}\label{eq45} E(t)\leq E(0)e^{-\kappa\xi(t)},\quad t>0. \end{equation}
(45)

Author Contributions

All authors contributed equally to the writing of this paper. All authors read and approved the final manuscript.

Competing Interests

The author(s) do not have any competing interests in the manuscript.

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